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6 - 2|3x + 2| = -12
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@thebro55
try this one
Whenever we deal with a absolute value in an equality, we have to apply the definition, and solve two equations independantly. Absolute value is defined: \[1) \left| a \right|= a <=> a>0\] \[2)\left| a \right|=-a <=> a<0\] it only means, that the absolute value can vary, depending on the values we take for the set of variables. so taking the problem: \[6-2\left| 3x+2 \right|=-12\] we will look at the definition applied to the absolute value: \[1)\left| 3x+2 \right|=(3x+2)<=> (3x+2)\ge0\] \[2)\left| 3x+2 \right|=-(3x+2)<=> (3x+2)<0\] So let's solve them both ways: \[1) 6-2(3x+2)=-12\] \[2) 6-2(-(3x+2))=-12\]
you have such detailed answers you must be really smart
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