Question

simple math problem but i forgot how to do it

Answer 1

hummmm... SIMPLE. math simplification...

Answer 2

let's see how simple it is...

Answer 3

sorry my computer was freezing

Answer 4

it is lmao. I did this like a few years go but i forgot how to do it now lol. Not sure if I use ln or e or something you know?

Answer 5

anyone know...? solving for m

Answer 6

I would start by simplifying the left side
can you simplify 1.2/38.4 ?

Answer 7

I don't particularly like decimals, so I would multiply top and bottom by 10
10/10 is one, so that does not change the value.
\[ \frac{12}{384} \]

Answer 8

ya i get that part lol

Answer 9

what did you get ?

Answer 10

that's not my concern I'm just not sure where i get the m value

Answer 11

like i can do that side of the problem. but what's next

Answer 12

I would write the right side as
\[ 0.5^2 \cdot \frac{1}{2^2} \cdot \left(\frac{\frac{1}{2}}{1}\right)^m \]

Answer 13

change 0.5 to 1/2
\[\frac{1}{2^2} \cdot \frac{1}{2^2} \cdot \left(\frac{\frac{1}{2}}{1}\right)^m \]

Answer 14

ok

Answer 15

what about my m? LOL how do i get rid of it??

Answer 16

m is still there
but I did use a^m / b^m = (a/b)^m

Answer 17

ya all expect like 1+1 -_-

Answer 18

i understand that haha but i want to get rid of it now

Answer 19

pretty sure m equals 1

Answer 20

what did you get for the left side ?

Answer 21

.5 so i just plugged in what i thout would make m equal that and so 1 workss!

Answer 22

I got
\[ \frac{12}{384} = \frac{1}{2^2} \cdot \frac{1}{2^2} \cdot \left(\frac{\frac{1}{2}}{1}\right)^m \]
which simplifies to
\[ \frac{1}{32} = \frac{1}{16} \cdot \left(\frac{1}{2}\right)^m \]
or
\[\frac{16}{32} = \left(\frac{1}{2}\right)^m \]
\[ \frac{1}{2}= \left(\frac{1}{2}\right)^m \]

it does not take any fancy logarithms to see m=1

Answer 23

ya i got it. thanks thats why i said it is easy.. BUT if it was not easy i wanted to know what logarithms you would use. That was just a random ex i found on the net

Answer 24

if you had for example

\[ 3 = 2^m \]
you would "take the log" of both sides
\[ \log(3) = \log(2^m) \]
where I am assuming log base 10 (because your calculator knows how to do this)
then use this "rule"
\[ \log(a^b) = b \log(a) \]
to rewrite as
\[ \log(3) = m\log(2) \]
divide both sides by log(2):
\[ \frac{\log(3)}{\log(2)} = m \]
now you use a calculator

Answer 25

that's what it was! thanks! Exactly what i was looking for! After a few years u forget those simple properties! Thanks again :)