Question

Suppose that a coyote spots a roadrunner 120 m away. If the coyote runs toward the roadrunner at a speed of 18 m/s and the roadrunner runs away at a speed of 10 m/s, how long will it take the coyote to catch up with the roadrunner?

Answer 1

looks like one of those distance equals rate times time problem

Answer 2

the coyote's distance is \(D=18T\) and the roadrunners is \(D=120+10
t\)

Answer 3

the 120 because he (she) has a 120 m head start
since they meet at the same distance, you can solve this by setting
\[18T=120+10
t\] and solve for \(T\)