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Mathematics 12 Online
OpenStudy (anonymous):

Subtract and simplify: (4p2q – pq2 + q3) – (3p2q + 2pq2– q3) A. p2q – 3pq2+2q3 B. p2q – 2pq2 C. p2q – 3pq2 D. 2p2q – 3pq2 Cna you help me simplify the problem? @KendrickLamar2014

OpenStudy (kendricklamar2014):

Ok this is kind of long so have patience :)

OpenStudy (anonymous):

Ok. :)

OpenStudy (anonymous):

I changed the equation to addition, would you like to correct my work so far?

OpenStudy (kendricklamar2014):

Yes please

OpenStudy (anonymous):

Okay :) Just give me a minute to type it in.

OpenStudy (kendricklamar2014):

Ok

OpenStudy (anonymous):

Okay, combine like terms. Then you get the answer of A. Need more clarification?

OpenStudy (kendricklamar2014):

Please @DIDITHEDAD we are trying to learn not give answers.

OpenStudy (anonymous):

I understand that, and I didn't. @BlossomCake Do you need more clarification about combining like terms?

OpenStudy (kendricklamar2014):

Combining Like Terms isn't even the first step, that's the last step

OpenStudy (anonymous):

\[(4p^2q - pq^2 + q^3) - (3p^2q + 2pq^2 - q^3)\]\[(4p^2q - pq^2 + q^3) + (-3pq^2) + (-2pq^2) + (-1q^3)\]

OpenStudy (anonymous):

Thanks for wanting to help, but I would rather go over the problem one-on-one so that I can understand what I am learning. Thanks anyways. :) @DIDITHEDAD

OpenStudy (anonymous):

Oh, sorry. Forgot about that. I always do that in my head and forget to write it down lol. First, multiply the RIGHT set by -1 THEN combine the like terms. Does that make more sense?

OpenStudy (anonymous):

Okay, feel free to tag me anytime!

OpenStudy (anonymous):

Anyways, I believe the next step is to combine the like terms after what I just did... Right? @KendrickLamar2014

OpenStudy (anonymous):

Yes, I know I have to multiply the right set by -1. :P And yes, it makes sense. @DIDITHEDAD

OpenStudy (kendricklamar2014):

Yes, can you Combine Like Terms by yourself or do you need me to explain the steps??

OpenStudy (anonymous):

I will try :D

OpenStudy (kendricklamar2014):

\[by~ the~ way~ its~ 1q^3 or ~q^3 \]

OpenStudy (kendricklamar2014):

not -1q^3 ^

OpenStudy (anonymous):

\[(4p^2q - pq^2 + q^3) - (3p^2q + 2pq^2 - q^3) \]\[(4p^2q - pq^2 + q^3) + (-3pq^2) + (-2pq^2) + (-1q^3) \]\[(4p^2q) + (-1pq^2 + -3pq^2 + -2pq^2) + (q^3 + -q^3)\]\[(4p^2q) + (-6pq^2)\]

OpenStudy (anonymous):

Wait! I did something wrong!

OpenStudy (kendricklamar2014):

Yes, your answer is wrong

OpenStudy (kendricklamar2014):

Step-By-Step: Combine Like Terms: 4p^2q + -pq^2 + q^3 + -3p^2q + -2pq^2 + q^3

OpenStudy (anonymous):

\[(4p^2q - pq^2 + q^3) - (3p^2q + 2pq^2 - q^3) \]\[(4p^2q - pq^2 + q^3) + (-3p^2q) + (-2pq^2) + (-q^3) \]\[(4p^2q + -3p^2q) + (-1pq^2 + -2pq^2) + (q^3 + -q^3)\]\[(1p^2q) + (-3pq^2)\]

OpenStudy (anonymous):

OR

OpenStudy (kendricklamar2014):

\[= (4p^2q + -3p^2q) + (-pq^2 + -2pq^2)+(q^3 + q^3)\]

OpenStudy (kendricklamar2014):

That answer ^ is almost right, you just forgot something

OpenStudy (anonymous):

\[(4p^2q - pq^2 + q^3) - (3p^2q + 2pq^2 - q^3) \]\[(4p^2q - pq^2 + q^3) + (-3p^2q) + (-2pq^2) + (-q^3) \]\[(4p^2q + -3p^2q) + (-1pq^2 + -2pq^2) + (q^3 + -q^3) \]\[(p^2q) + (-3pq^2)\]

OpenStudy (anonymous):

The q^3 cancels the other one out, right?

OpenStudy (kendricklamar2014):

You forgot to add:\[q^3 + q^3\]

OpenStudy (kendricklamar2014):

They don't cancel out because there both positives <--- theres ur mistake

OpenStudy (anonymous):

Are you sure about that?

OpenStudy (kendricklamar2014):

Yup

OpenStudy (anonymous):

Hmm... Ok.

OpenStudy (kendricklamar2014):

\[Answer: p^2q - 3pq^2 + 2q^3\]

OpenStudy (anonymous):

Are you sure it's not C. ??

OpenStudy (anonymous):

How does it become: \[2q^3\]

OpenStudy (kendricklamar2014):

100% sure its A

OpenStudy (kendricklamar2014):

\[1q^3 + 1q^3 = 2q^3\]

OpenStudy (anonymous):

Oh! Okay, now I understand! :D

OpenStudy (kendricklamar2014):

Yay

OpenStudy (anonymous):

Thanks for your help, again!

OpenStudy (kendricklamar2014):

No Problem

OpenStudy (anonymous):

Can you check my next one? @KendrickLamar2014

OpenStudy (anonymous):

I can post a new question and you can check it their....

OpenStudy (kendricklamar2014):

OK, sounds good

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