Complete the equation for the linear function whose graph contains the points
(9, 7) and (4, –8).
y −?? =?? (x − 9)
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OpenStudy (anonymous):
@iGreen @Nnesha
OpenStudy (igreen):
Plug the points in the slope formula and find the slope.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
-2 and -12
OpenStudy (igreen):
No..
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OpenStudy (igreen):
-8 = y2
7 = y1
4 = x2
9 =x1
OpenStudy (anonymous):
and then divide right
OpenStudy (igreen):
Yep
OpenStudy (anonymous):
2 and 2
OpenStudy (igreen):
No..
\(\dfrac{-8 - 7}{4 - 9}\)
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OpenStudy (anonymous):
-15/-5=3
OpenStudy (anonymous):
still confused DX
OpenStudy (igreen):
Correct.
OpenStudy (igreen):
So the slope is 3.
\(y - y_1 = m(x - x_1)\)
Where \(y_1\) is the y-value of the point, \(x_1\) is the x-value of the point, and \(m\) is the slope.
So we have:
\(y - y_1 = 3(x - 9)\)
So do you know what 'y1' is going to be?
OpenStudy (anonymous):
is it kinda the same thing when we figured out the other one.
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OpenStudy (igreen):
?
OpenStudy (igreen):
Sort of
OpenStudy (igreen):
What is in the 'x1' place?
OpenStudy (anonymous):
9
OpenStudy (igreen):
Yes, so the point must have a '9' for the 'x'
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OpenStudy (igreen):
Which one of our points has that?
OpenStudy (anonymous):
(9,7)
OpenStudy (igreen):
Correct, and what's the y-value?
OpenStudy (anonymous):
I gtg D: so cya
OpenStudy (igreen):
Oh, well the y-value is 7..so that goes at 'y1'.
\(y - 7 = 3(x - 9)\)