Question

In a certain lottery, five different numbers between 1 and 20 inclusive are drawn. To win the lottery, a person must select the correct 5 numbers in the same order in which they were drawn. What is the probability of winning?

Answer 1

To solve this question you need to find the number of permutations of the 20 numbers taken 5 at a time:
\[\large P(20, 5)=\frac{20!}{(20-5)!}=you\ can\ calculate\]
When you have this number, the inverse of it is the solution.

Answer 2

just give the answer please??

Answer 3

We are not supposed to give out answers. But rather guide you and help you get there.

Well your chance of getting the first right is 1/20 then 1/19 and so on until 1/16 for the fifth ball.

Here's why:

So 1/(20*19*18*17*16) = 1/860,480

Another way to write the answer is 1/P(20,5) or 1/20P5 where nPk = P(n,k) = C(n,k) * k!
and C(n,k) is binomial coefficient and k! is factorial.

Hope that helps.

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