(3ab^7)^4
What is the question?
81a^4b^28
I have to simplify it and I also don't just want the answer I want to know how to do it
exponent property... if you raise and exponent to another, you multiply them (a^x)^d = a^xd
so 3^1 becomes 3^4 because 1 *4 = 4 so a^1 becomes a^4 because 1*4 = 4 so b^7 becomes b^28 because 7*4 = 28
@Austin6i6 that's correct. When distributing exponentials, you always raise the constant terms by the exponent so we have 3^4=81 . You raise the variables to the exponent as well. So we have a^4 , and for variables with exponents we multiply the exponents together, so (b^7)^4 = b^28. So our final answer is 81(a^4)(b^28)
So I would multiply them all by 4?
same as (3ab^7)*(3ab^7)* (3ab^7)* (3ab^7)
exponent notation looks like this (ab)^5 = (ab)*(ab)*(ab)*(ab)*(ab)
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