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Mathematics 7 Online
OpenStudy (anonymous):

(3ab^7)^4

OpenStudy (anonymous):

What is the question?

OpenStudy (anonymous):

81a^4b^28

OpenStudy (anonymous):

I have to simplify it and I also don't just want the answer I want to know how to do it

OpenStudy (anonymous):

exponent property... if you raise and exponent to another, you multiply them (a^x)^d = a^xd

OpenStudy (anonymous):

so 3^1 becomes 3^4 because 1 *4 = 4 so a^1 becomes a^4 because 1*4 = 4 so b^7 becomes b^28 because 7*4 = 28

OpenStudy (anonymous):

@Austin6i6 that's correct. When distributing exponentials, you always raise the constant terms by the exponent so we have 3^4=81 . You raise the variables to the exponent as well. So we have a^4 , and for variables with exponents we multiply the exponents together, so (b^7)^4 = b^28. So our final answer is 81(a^4)(b^28)

OpenStudy (anonymous):

So I would multiply them all by 4?

OpenStudy (anonymous):

same as (3ab^7)*(3ab^7)* (3ab^7)* (3ab^7)

OpenStudy (anonymous):

exponent notation looks like this (ab)^5 = (ab)*(ab)*(ab)*(ab)*(ab)

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