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Mathematics 9 Online
OpenStudy (countrygirl1431):

Can someone tell me how to go about doing this problem??

OpenStudy (countrygirl1431):

What is the length of AA' ?

OpenStudy (countrygirl1431):

OpenStudy (anonymous):

u said the length of aa as point a to point a

OpenStudy (countrygirl1431):

im not really sure

OpenStudy (anonymous):

\[x ^{2}=5^{2}+2^{2}\]

OpenStudy (anonymous):

do this u will get

OpenStudy (anonymous):

consider a,a^ and point 5 as a right angled triangle

OpenStudy (anonymous):

u will get \[\sqrt{29}\]

OpenStudy (countrygirl1431):

i just got that so for this type of problem i just square the number?

OpenStudy (anonymous):

yes (apply Pythagoras thoeram)

OpenStudy (countrygirl1431):

oh ok i get it now thanks

OpenStudy (countrygirl1431):

can u help me with one more

OpenStudy (anonymous):

sure

OpenStudy (countrygirl1431):

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance A'B'

OpenStudy (countrygirl1431):

OpenStudy (anonymous):

apply same formula

OpenStudy (countrygirl1431):

so 2 squared and 5 squared

OpenStudy (anonymous):

\[x ^{2}=1^{2}+3^{2}\]

OpenStudy (anonymous):

u will get\[\sqrt{10}\]

OpenStudy (countrygirl1431):

im confused

OpenStudy (countrygirl1431):

do you go by the y axis or the x axis

OpenStudy (anonymous):

take right angled triangle like this

OpenStudy (anonymous):

did u understand?

OpenStudy (countrygirl1431):

not really

OpenStudy (anonymous):

take base as 1 and height as 3

OpenStudy (countrygirl1431):

ok

OpenStudy (anonymous):

now do u understand?

OpenStudy (countrygirl1431):

i think im getting it

OpenStudy (countrygirl1431):

thanks

OpenStudy (anonymous):

ur welcome

OpenStudy (anonymous):

u can ask me any doubts from anything

OpenStudy (anonymous):

but its late for me

OpenStudy (anonymous):

byeee

OpenStudy (anonymous):

@countrygirl1431 before leaving u refer my research and give me some comments

OpenStudy (countrygirl1431):

???

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