Mathematics
9 Online
OpenStudy (countrygirl1431):
Can someone tell me how to go about doing this problem??
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OpenStudy (countrygirl1431):
What is the length of AA' ?
OpenStudy (countrygirl1431):
OpenStudy (anonymous):
u said the length of aa as point a to point a
OpenStudy (countrygirl1431):
im not really sure
OpenStudy (anonymous):
\[x ^{2}=5^{2}+2^{2}\]
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OpenStudy (anonymous):
do this u will get
OpenStudy (anonymous):
consider a,a^ and point 5 as a right angled triangle
OpenStudy (anonymous):
u will get \[\sqrt{29}\]
OpenStudy (countrygirl1431):
i just got that so for this type of problem i just square the number?
OpenStudy (anonymous):
yes (apply Pythagoras thoeram)
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OpenStudy (countrygirl1431):
oh ok i get it now thanks
OpenStudy (countrygirl1431):
can u help me with one more
OpenStudy (anonymous):
sure
OpenStudy (countrygirl1431):
Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.
Find the distance A'B'
OpenStudy (countrygirl1431):
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OpenStudy (anonymous):
apply same formula
OpenStudy (countrygirl1431):
so 2 squared and 5 squared
OpenStudy (anonymous):
\[x ^{2}=1^{2}+3^{2}\]
OpenStudy (anonymous):
u will get\[\sqrt{10}\]
OpenStudy (countrygirl1431):
im confused
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OpenStudy (countrygirl1431):
do you go by the y axis or the x axis
OpenStudy (anonymous):
take right angled triangle like this
OpenStudy (anonymous):
did u understand?
OpenStudy (countrygirl1431):
not really
OpenStudy (anonymous):
take base as 1 and height as 3
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OpenStudy (countrygirl1431):
ok
OpenStudy (anonymous):
now do u understand?
OpenStudy (countrygirl1431):
i think im getting it
OpenStudy (countrygirl1431):
thanks
OpenStudy (anonymous):
ur welcome
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OpenStudy (anonymous):
u can ask me any doubts from anything
OpenStudy (anonymous):
but its late for me
OpenStudy (anonymous):
byeee
OpenStudy (anonymous):
@countrygirl1431 before leaving u refer my research and give me some comments
OpenStudy (countrygirl1431):
???
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