find the mean median mode... ( 40,43,46,46,48.49.57 )
for the mean I add 40,43,46,46,48,49,57/2
what grade are you really in. the truth
7th we were suppose to learn this last yearin 6th grade but we had to skip it :/ I recently learned this
I got 47 for mean I divided by ammount of numbers there were
amount
Mean = 47 is correct :) know how to find median?
yes I check if theres 2 middle numbers if there isnt the medians already there
I just need someone to help me if I make a mistake
i'm here :) since we have 7 numbers, we'll have only one middle number!
To find the Median, place the numbers you are given in value order and find the middle number. Example: find the Median of {13, 23, 11, 16, 15, 10, 26}. The middle number is 15, so the median is 15. (If there are two middle numbers, you average them.)
yes if its even we would have to the numbers + eachother / 2
the important point is , you need to *sort* the numbers
yes Thats what I did already and the mode is appearing more then once right???? If so its 46,46
how do I add this into a weather chart now thats what I need help on
I mean graph
wait, what did u get median as?
since the numbers are already sorted, median = middle number here
The mode is the value that appears most often in a set of data.
median is 57
40,43,46,46,48.49.57 i see 46 is the middle number so its the median
I mean 46 my bad
I was looking at my worksheet before I organized it
ok, np :) and mode will be 46 too right? as it appeared twice
yes
good :) any other doubts?
I am making a graph right now for it I am doing an extra credit assignment but u didnt really help me only with one thing but that was an answer i already knew u told me the basics of it thanks so much
Mode=the number that is put in the most Mean=all the numbers added then divided bye how many numbers you added Median=Is then number that is in the middle so it would be 46 in this problem Range= Is the largest number and the smallest number subtracted together And that should help I found it off of purplemath.com
welcome ^_^ good luck with extra credits :) let me know if you need help with graphs :)
ok tysn
Join our real-time social learning platform and learn together with your friends!