Question

The curve C has the equation y=(x-a)^2, where a is constant.
Given that dy/dx = 2x-8 find the value of a

Answer 1

HI!!
make
\[x^2-8x\] a perfect square

Answer 2

So, you got that from integrating dy/dx? and hello :)

Answer 3

So \[(x-4)^2 + 8\]?

Answer 4

i would say \[(x-4)^2=x^2-8x+16\] so yeah

Answer 5

actually not what you said, they are only asking you to make it \((x-a)^2\) so the answer is \((x-4)^2\)

Answer 6

So a would = 4 or -4?