Question

Help with Trig please!

Answer 1

I already did part of the question, just stuck at the last bit. \[\frac{ \sqrt{3} }{ 2 } - \frac{ 1 }{ \sqrt{2} } - \cot \frac{ 9\pi }{ 2 }\]

How do I convert cot 9pi/2?

Answer 2

cot = 1/tan

Answer 3

1/tan(9pi/2)

Answer 4

Yeah, but like. 9pi/2 = 810 degrees, wihch also means 90 degrees, and the tan of 90 degrees is something like 1.6331239e+16.

Answer 5

yes it is 90 deg.
do you know what cos 90 and sin 90 are?

Answer 6

1 for sin, 0 for cos

Answer 7

so tan is sin/cos

Answer 8

Wait why? o_O

Answer 9

its a property tan = sin/cos

Answer 10

but since its inverse 1/tan = cos/sin

Answer 11

Ohhhh. So \[\frac{ \frac{ o }{ h } }{ \frac{ a }{ h }} = \frac{ 0 }{ a } = tangent?\]

Answer 12

Thus the cot of 90 degrees = 0?

Answer 13

correct! nice job

Answer 14

\[\frac{ \sqrt{3} - \sqrt{2} }{ 2 }\] Must be the answer to this question right?

Answer 15

yes