Question

For the function given, state the starting point for a sample period:
f(t)=3cos(pit−1)

Answer 1

put
\[\pi t-1=0\] solve for \(t\)

Answer 2

then put \[\pi t-1=2\pi\] and solve for \(t\)

Answer 3

as far as i know there is no such thing as a "starting point" for a period
if a function is periodic with period \(p\) it means
\[f(x)=f(x+p)\] for all \(x\)
there is no "starting point" or "ending point"

Answer 4

could you give me the answer, pls?