Question

help me please

http://prntscr.com/6ikvrb

Answer 1

What is \[4^{1} =?\]

Answer 2

plug in the given x values in the function, your output will be the y value

Answer 3

wait but look at the 4)^-x
why is there only one ) ??

Answer 4

That's a mistake. It should read \[g(x)=4^{-x}=(4)^{-x}\] makes no difference.

Answer 5

It's probably just a typo.
Notice that at x = -2, g(-2) = 16
If \(g(x) = 4^{-x} \), then at x = -2, \(g(-2) = 4^{-(-2)} = 4^2 = 16\)
Also, \(g(x) = 4^{-x}\) works with x = 0 to give g(0) = 1.
Just ignore the right parenthesis.

Answer 6

ok so let me do the math real quick