Eliminate the parameter.

$x = t^2 + 1, y = t^2-1$

$y = x + 2, x \ge 1\
y = x - 2, x \ge 1\
y = x^2 - 2, x \ge 1\
y = x^2 + 2, x \ge 1$

Question

Eliminate the parameter.

$x = t^2 + 1, y = t^2-1$

$y = x + 2, x \ge 1\
 y = x - 2, x \ge 1\
 y = x^2 - 2, x \ge 1\
 y = x^2 + 2, x \ge 1$

sleepyjess · Answer

I'm getting stuck on this one
@phi  @xapproachesinfinity

phi · Answer

if x= t^2 + 1,   x is positive (right ?).  In fact $ t^2 \ge 0 $ , so $x \ge 0+1  $

solving for t^2 :    t^2=  x-1
putting that in the 2nd equation
y = t^2 -1
y = x-1 - 1

y=  x-2;   x $ \ge$1

sleepyjess · Answer

Aha! That is what I was doing wrong, I was attempting to solve for t instead of $t^2$ >.<

xapproachesinfinity · Answer

eh no just solve fo t^2 lol

phi · Answer

yes, you must be sly like a fox sometimes

sleepyjess · Answer

haha
thanks :)

xapproachesinfinity · Answer

hehe true!

xapproachesinfinity · Answer

don't worry i feel dumb sometimes trying such thing, in fact, it happens to me quite many times lol