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OpenStudy (ashchu117):
omg XD
OpenStudy (ashchu117):
ok hahaha gimme a sec
OpenStudy (ashchu117):
or 840
OpenStudy (ashchu117):
(the vid is 14mins long and there are 840 seconds in that amount of time)
OpenStudy (ashchu117):
yeah I got lost 2 mins into it @Andrewthehelper @sleepyjess
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OpenStudy (lilshane):
if this is not a question plz cloes this
pooja195 (pooja195):
this is a question -_- a MATH one
OpenStudy (ashchu117):
I attached the question as an image @lilshane
OpenStudy (ashchu117):
thx @pooja195
OpenStudy (anonymous):
efforless method.. check from the options about the sum and the product of root
technical method... 1. Make the coeff of x^2 = 1 (take out 3 from the whole equation)
2 add and subtract the half of the coeff of x (+9 - 9 )
3. complete the square you got all the terms
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OpenStudy (lilshane):
ok im so sorry @Ashchu117
OpenStudy (ashchu117):
np @lilshane
OpenStudy (ashchu117):
wowowow wait @divu.mkr can you like draw it out or something please cuz thats too much math talk 4 me to understand
OpenStudy (ashchu117):
.-.
OpenStudy (ashchu117):
I'm like a 2nd grade idiot here lol (im really in 8th grade tho and im in Algebra 1 honors)
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OpenStudy (anonymous):
give it a shot... i will try to assist you.!
OpenStudy (ashchu117):
ok so if we make the coefficient x^2 then the new equation would look like 3(x^2)2 = 6; x = −3 + square root 2, x = −3 − square root 2.................. right?
OpenStudy (ashchu117):
oops wait
OpenStudy (ashchu117):
3(x^2) = 6; x = -3 + square root 2, x = -3 - square root 2
OpenStudy (ashchu117):
yes or no?
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OpenStudy (anonymous):
you checked for sum and product?
OpenStudy (ashchu117):
I don't know how to do that or what that means
OpenStudy (ashchu117):
like I said im an idiot :P
OpenStudy (anonymous):
i am trying to say that the product of the two roots in a quadratic equation is -(coeff of x)/ (coeff of x^2)
and product = constant term/(coeff of x^2)
give a check for product and sum from the options
OpenStudy (ashchu117):
oops wait i copied the wrong answer XD
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OpenStudy (ashchu117):
hold up
OpenStudy (ashchu117):
*wrong equation not answer sorry
OpenStudy (ashchu117):
x^2 + 18x + 15 = 0 <- so there's step one
OpenStudy (ashchu117):
("<-" is an arrow, not part of the equation)
OpenStudy (anonymous):
you dint took 3 out of the whole equation... you just took out from x^2
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OpenStudy (ashchu117):
ooohhhh so its x^2 + 15x + 12 = 0
OpenStudy (ashchu117):
or just x^2 + 15x + 15 = 0 ?
OpenStudy (ashchu117):
ok so submitted it and I chose A....... A was wrong................