Question

Will someone please help me with these math questions? When providing the answer, can you also provide an explanation, if possible, so I understand it?

Select the coordinates of two points on the line y = -2.

(2, -2) and (-2, 2)
(-2, -2) and (-2, 0)
(2, -2) and (0, -2)
(-2, 2) and (-2, -2)

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

y = four thirdsx + 8
y = four thirdsx + 3
y = -three fourthsx + 8
y = -three fourthsx + 3

Answer 1

1. Line y=-2 is simply a straight line that intersects the y-axis at -2, therefore, both y intersect points need to be at y=-2. This allows us to eliminate all answers except (c): (2, -2) and (0, -2).

Answer 2

Thank you so much, hun! This is really helping me out!

Answer 3

2 is a little harder...

From converting the given line to slope-intercept form,

4x - 3y = - 12
-3y = -4x - 12
y = - 4/3x - 12

We get the slope, -4/3.
Now, we use the equation y-y_1=m(x-x_1) to find the slope-intercept form of the parallel line.

Plug in our intercept point (-3, 4)
y = m(x - (-3))
Plug in m (the slope):
y = -4/3 (x - (-3))
Then add m onto x to get into slope-intercept form:
y = -4/3 (x + 3)
y = -4/3x + 3

The only problem is that none of your choices has this equation...