Question

Help solving trig equations

Answer 1

\[\sqrt3\cot(\theta)-1=0\] Express the answer in degree measure

Answer 2

cot=cos(theta)/sin(theta)

Answer 3

@mathmath333

Answer 4

does this help? \(\dfrac{cos(\theta)}{sin(\theta)}=\dfrac{1}{\sqrt3}\)

Answer 5

try to convert \(\cot \theta \) into \(\tan \theta \)

Answer 6

well to do that it would be 1/tan=1/3

Answer 7

1/sqrt3*

Answer 8

then you could flip it to be tan(theta)=sqrt3

Answer 9

and then http://www.pinkmonkey.com/studyguides/subjects/trig/chap2/a16.gif

Answer 10

so 30 degrees?

Answer 11

tan(30)=1/sqrt(3)

Answer 12

what we have is tan(theta)=sqrt3

Answer 13

Alright. How would we find the next measurement

Answer 14

or am I thinking wrong

Answer 15

use the fact that \(\ tan x=\tan(\pi+x)\)

Answer 16

it's pi/3 because \(\cot(\theta)=\dfrac{1}{\sqrt3}\\tan(\theta)=\sqrt3\\\theta=\dfrac{\pi}{3}+n\pi\)

Answer 17

I'm just going off the table. tan theta = 60 degrees when theta = sqrt3

Answer 18

oks s: so that is like saying 60+180?

Answer 19

180n (n is an integer)

Answer 20

so basically
\(tan(\theta)=\dfrac{1}{\sqrt3}\implies \theta=\dfrac{\pi}{3},\dfrac{4\pi}{3},...\)

Answer 21

Ok thank you so much for explainging :3