The system shown below contains two blocks of mass m1 and mass m2 and a pulley with moment of inertia I and radius r. There is no friction between m2 and the horizontal surface. Likewise, there is no friction in the pulley's axle.
Given:
Torque(net) = T1*r - T2*r = I*alpha
and
a(tangential) = alpha * r

Now suppose that m1=0.8 kg, m2=2.4 kg, I=2.8 kg*m^2, and r=0.24 m. What is the value of the pulley's angular acceleration alpha, in radians per second per second?

Question

The system shown below contains two blocks of mass m1 and mass m2 and a pulley with moment of inertia I and radius r. There is no friction between m2 and the horizontal surface. Likewise, there is no friction in the pulley's axle.
Given:
Torque(net) = T1*r - T2*r = I*alpha
and
a(tangential) = alpha * r

Now suppose that m1=0.8 kg, m2=2.4 kg, I=2.8 kg*m^2, and r=0.24 m. What is the value of the pulley's angular acceleration alpha, in radians per second per second?

jaredstone4 · Answer

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jaredstone4 · Answer

@jdoe0001 You have a high rating on here and look like you might know some physics. Any chance you could help? I'm so lost haha.

irishboy123 · Answer

you need 2 additional equations, for the acceleration of the blocks

T2 = m2 a
mg - T1 = m1a

then rearrange and sub the T1, T2 you get into the equation for the angular acceleration and it all comes out quite easily