The graph of a limacon curve is given. Without using your graphing calculator, determine which equation is correct for the graph. http://prntscr.com/6k5yum [-5, 5] by [-5, 5] r = 2 + 2 sin \(\theta\) r = 3 + sin \(\theta\) r = 1 + 3 cos \(\theta\) r = 1 + 3 sin \(\theta\)
@perl
r = 1 + 3 sin θ is the answer
Can you explain why please?
@praneet_r ?
yeah, the sin makes it surround the y axis. In the standard form, \[r=a \pm b \sin \theta\], a/b becomes smaller as the loop becomes bigger
Oh, okay :) Thanks!
you can also plug in values , theta = 0, pi/4, pi/2, pi, 3pi/2, 2pi
@perl thats also a way to do it
@praneet_r a/b becomes smaller as the inner loop becomes bigger, is that correct? can you justify this
i shouldn't have said it like that. it makes more sense to say that when a/b is less than 1, then the limacon has an inner loop
@perl
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