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Mathematics 11 Online
OpenStudy (sleepyjess):

The graph of a limacon curve is given. Without using your graphing calculator, determine which equation is correct for the graph. http://prntscr.com/6k5yum [-5, 5] by [-5, 5] r = 2 + 2 sin \(\theta\) r = 3 + sin \(\theta\) r = 1 + 3 cos \(\theta\) r = 1 + 3 sin \(\theta\)

OpenStudy (sleepyjess):

@perl

OpenStudy (anonymous):

r = 1 + 3 sin θ is the answer

OpenStudy (sleepyjess):

Can you explain why please?

OpenStudy (sleepyjess):

@praneet_r ?

OpenStudy (anonymous):

yeah, the sin makes it surround the y axis. In the standard form, \[r=a \pm b \sin \theta\], a/b becomes smaller as the loop becomes bigger

OpenStudy (sleepyjess):

Oh, okay :) Thanks!

OpenStudy (perl):

you can also plug in values , theta = 0, pi/4, pi/2, pi, 3pi/2, 2pi

OpenStudy (anonymous):

@perl thats also a way to do it

OpenStudy (perl):

@praneet_r a/b becomes smaller as the inner loop becomes bigger, is that correct? can you justify this

OpenStudy (anonymous):

i shouldn't have said it like that. it makes more sense to say that when a/b is less than 1, then the limacon has an inner loop

OpenStudy (anonymous):

@perl

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