A box has 5 beads of the same size, but all are different colors. Tina draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tina would pick a red bead on the first draw, then a green bead, and finally a red bead again? Answers: 1/625, 1/180, 1/150, 1/125 please help me understand I have no idea how to do this
ok so do you understand probability
yes mostly
ok ok so there are 5 beads of the same size in the box all in different colors
she draws a bead 4 times
and there are 5 beads out of the four times she draws a bead which means it is 4/5
now find a fraction equivalent to that
a fraction equivalent would be like 8/10 but the answers are all 1 as the numerator and then a big number as the denominator
the probability of picking any one bead is 1 out of 5. since the bead is replaced each time then the probabilty of choosing any of the beads for the next pull is still 1/5
1/5 * 1/5 * 1/5 seems to make the most sense to me
spose there is no replacement the probability of pulling a red first is 1/5 the probability of then pulling a green is 1/4 the probability of pulling a red next is 0 but since we replace the bead each time the probability of pulling any bead remains 1 out of 5 for any given pull
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