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A small mass m is supported by a vertical spring. When an additional 100 g is attached to the original mass the system begins to oscillate at a frequency of 0.500 Hz. When the oscillations die out the spring is found to have increased in length by 10.0 cm. Find m.
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237 N
so m have to mass of 24.18 kg?
@hijamya321
I have found k by solving k from \[F_s=k*\Delta y \], so \[k= F_s/\Delta y\] \[k= (0.1kg * 9.8m/s^2) / 0.1m => k=9.8N/m \] \[T=2\pi \sqrt{m/k} => solve.for.m => m=k*T^2 / 4\pi^2\] the answear is suppose to be 893 grams. Cant get it right.
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