Determine which consecutive integers do NOT have a real zero of f(x)=x^3-9x^2+23x-14. a. (4,5) b. (-1,0) c. (3,4) d. (0,1)
c
I'd probably test the pair, using the "remainder theorem"
what would i be dividing the equation by??
You have to plug in each x value one at a time. eg: (4,5) first plug x=4 into x^3-9x^2+23x-14 then plug x=5 into x^3-9x^2+23x-14 if the result from x=4 is positive, and the result from x=5 is negative (or the first is negative and the second is positive) there's a zero in there somewhere.
im glad you know how to copy and paste from other posts alyssa lmfao
@chlobohoe I figured it would help you?? you asked the question no need to be rude.
LOL says the one who first called me a 'bi/tch'. if i needed help i could already find i wouldnt resort to this website.
@chlobohoe you don't have to be a "bi/tch' i was only trying to help. you could @ me next time if wanna continue to get smart.
hahaha wow hun youre getting so salty. if i wanted to '@' trash id call the garbage can. thanks for nothing tho dont expect any call in the future
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