find the polar equation for...

Question

anonymous · Answer

$$x ^{2}+y ^{2}-4x+6y=0$$

anonymous · Answer

yeah haha i don't know how to do that

perl · Answer

:)

anonymous · Answer

i can make it a circle but converting to polar?

perl · Answer

actually, collect x^2 + y^2 , that is equal to r^2

perl · Answer

disregard what i said earlier

perl · Answer

there are 4 equations to convert polar/rectangular equations
$$\Large{
x= r \cos 	heta \
y = r \sin 	heta  \
r^2 = x^2 + y^2\
	heta = arctan ( y/x)



}
$$

perl · Answer

$$
\Large {
x ^{2}+y ^{2}-4x+6y=0
\ \iff \
r^2 - 4( r \cos 	heta) + 6 ( r \sin 	heta) = 0 
\ \iff \ 
r^2 =  4( r \cos 	heta) - 6 ( r \sin 	heta)\
\ \iff \ 
r^2 = r ( 4\cos 	heta - 6  \sin 	heta) 
\ \iff \ 
r =  4\cos 	heta - 6  \sin 	heta


}
$$

anonymous · Answer

Thank you so much! Can you help me with another real quick?