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find the polar equation for...
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\[x ^{2}+y ^{2}-4x+6y=0\]
yeah haha i don't know how to do that
:)
i can make it a circle but converting to polar?
actually, collect x^2 + y^2 , that is equal to r^2
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disregard what i said earlier
there are 4 equations to convert polar/rectangular equations $$\Large{ x= r \cos \theta \\ y = r \sin \theta \\ r^2 = x^2 + y^2\\ \theta = arctan ( y/x) } $$
$$ \Large { x ^{2}+y ^{2}-4x+6y=0 \\ \iff \\ r^2 - 4( r \cos \theta) + 6 ( r \sin \theta) = 0 \\ \iff \\ r^2 = 4( r \cos \theta) - 6 ( r \sin \theta)\\ \\ \iff \\ r^2 = r ( 4\cos \theta - 6 \sin \theta) \\ \iff \\ r = 4\cos \theta - 6 \sin \theta } $$
Thank you so much! Can you help me with another real quick?
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