Find the perimeter of the following shape:
Shape ABCD is shown. Point A is at 7, 5. Point B is at 6, 3. Point C is at 3, 2. Point D is at 4, 4.
10.8
11
11.4
11.6
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OpenStudy (anonymous):
OpenStudy (welshfella):
this is a parallelogram with opposite sides equal so you only need to find the lengths of AB and BC
OpenStudy (anonymous):
So whats the next step?
OpenStudy (welshfella):
do you know the formula for the length of a line given the coordinates of its endpoints?
OpenStudy (anonymous):
No.
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OpenStudy (welshfella):
use this formula to find the lengths of AB and BC
OpenStudy (welshfella):
Ok its
Sqrt [ (y2-y1)^2 = (x2-x1)^^2]
where (x1,y1) and (x2,y2) are the 2 endpoints
OpenStudy (welshfella):
* that = should be a +
OpenStudy (welshfella):
so for point A we have x1 = 7 and y1 = 5
and for point B we have x2 = 6 and y2 = 3
plug these into the formula
OpenStudy (anonymous):
11.6?
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OpenStudy (welshfella):
how did you get that?
OpenStudy (welshfella):
AB = sqrt [(3-5)^2 + (7-6)^2] = sqrt(4 + 1) = sqrt5
opposite side CD = sqrt5
can you find the length of BC in a similar way?