Select the equation in which the graph of the line has a negative slope, and the y-intercept equals -4. 5x + 3y = 4 5x - 3y =-4 4x + 16y = -20 6x + 2y = -8
ok for each equation do the X and Y intercept do you know how?
\[5x + 3(0) = 4\] \[5(0) + 3y = 4\]
no, i really don't understand any of this, i am super behind in algebra and thought i remembered this stuff but i was sorely mistaken : ((
ok solve the equations i gave :)
I see hows its done.
okay, the first equation is ... 5x+3(0)=4 ... so first i multiply 3 * 0, which equals 0 of course. then the equation is 5x + 0 = 4, so we simplify it to 5x = 4. The second equation is ... 5(0)+3y=4 ... so that equation turns out to be 3y = 4 after we do the steps above again. is that correct ?
im not sure...anymore ;-; im gonna let someone else take this one this is confusing,,,
@sleepyjess @TheSmartOne
thats fine, i understand ! hopefully someone else can help
@pooja195 I think you are doing it right with the two equation things.
Idk either. But the equation part is correct i think. :)
idk
ill try
if thats the case then \[3y = 4 \] divide by 3 so 4/3 and then same with the other equation \[5x=4\] divide by 5 so 5/4
Right now, let's just use y = mx + b, then convert it to standard form. We know that the slope is negative, so -m, and that the y intercept is -4. So that gives us y = -mx - 4
Maybe... this is confusing. I know the answer, but I don't know how to explain. Or at least I think I know the answer
@amistre64 do you know?
when x=0, y=-4 is a solution that we can narrow the options with
theres only one option that satisfies this criteria
... 5x - 3y = -4 ?? :oo
Naw, I don't think that one is it.....because rearranging it you get 3y = 5x + 4 no -4, no negative slope, can't be.
Hmmm.. This is hard !!! Grr
The post by @sleepyjess tells you how to solve it, amistre64 shows a practical way to spot the correct solution. There is only one when placed in the slope intercept form has an intercept of -4.
Oh, so I was on the right track...
there were tracks?
yes, wise-tracks lol
lol
OK harley_may looking at the first two can you see we can eliminate them because the intercept is not a negative ?
Yes, I think I get that
those would be positive as well as improper value. Now look at the third one...what do you think. 4x + 16y = -20
First for kicks divide thru by 4 and look at it again.
Do you see: x + 4y = -5 intercept is negative but alas it is not a -4.
ohhh, i get that ! okay
finally look at the last one, 6x + 2y = -8 lets follow sleepyjess suggestion 2y = -6x -8 y=-3x - 4 in slope intercept form. what you think?
i see a negative four in there !! is that the answer ?
Yes, it has a negative slope (-6) and an intercept of -4 A perfect candidate .
thank you so so so much !!!
You're welcome, and wishing you good luck with your studies.
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