How can 1/5x – 2 = y and 1/3x +8 = y be set up as a system of equations?
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OpenStudy (anonymous):
1/5x-2 = 1/3x + 8
You can set each equal to y and you will have two equations:
y = 1/5x - 2
y = 1/3x + 8
multiply the first equation throughout by 5 to get rid of the fraction.
multiply the first equation throughout by 3 to get rid of the fraction.
In each equation, keep the constant on the right hand side and bring everything else to the left hand side.
OpenStudy (fionacndg):
Okay... let me process this!
OpenStudy (anonymous):
k
OpenStudy (fionacndg):
so would y = 1/5x - 2 --> y= 5x-10
OpenStudy (fionacndg):
@pielover123 so the first equation = -10 right? so what am i doing wrong or what do i do from here
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OpenStudy (anonymous):
your doing it right
OpenStudy (fionacndg):
okay and the second equals x+24
OpenStudy (anonymous):
Yes sir!
OpenStudy (fionacndg):
I have -34 as my answer. what do i do now?
OpenStudy (fionacndg):
here is an attachment for possible answers I have.
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OpenStudy (fionacndg):
@pielover123
OpenStudy (anonymous):
it would be the second one if i'm correct
OpenStudy (fionacndg):
Okay. is there a simple way I can check that?
OpenStudy (anonymous):
Not that i know of
OpenStudy (fionacndg):
Okay. thank you!!!!!
I am hoping that it is correct!
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OpenStudy (fionacndg):
unfortunately that wasn't the answer.
OpenStudy (anonymous):
Im sorry
OpenStudy (fionacndg):
Not like I could do any better! Thank you for your time! have awesome day!