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HELP PLEASE! simplify the radical expressions. state any excluded values. show your work. 1. 3x-6/x-2 2. x-2/x^2+3x-10
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combined like turms and bring all the x's together then combined the regular numbers
i've tried. i cant understand how to do it.. i suck at math..
\[1.~~\frac{3x-6}{x-2} = \frac{3(x-2)}{(x-2)} = \frac{3 \cancel{(x-2)}}{\cancel{(x-2)}} = 3\] \[2. ~~\frac{x-2}{x^2 + 3x - 10} = \frac{(x-2)}{(x+5)(x-2)} =\frac{\cancel{(x-2)}}{(x+5)\cancel{(x-2)}} = \frac{1}{(x+5)}\] Getting this? :)
getting it a little better. i suck at math bad..
3x goes with x so 4 x and 2 negitives equals a positive so -6 * -2 = 12 12/4x equals x =3
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ohhh
yeah 3 is the answer
so would x-2 be the excluded values? or would it be 3?
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