Hi everyone! Can someone explain to me step by step how to get from -x^2-2x+1 to 2-(x+1)^2 by factoring? I need to understand the steps without any magic! Thanks! :o)
\[-x^2 - 2x + 1\]\[= -x^2 - 2x \color{green}{- 1 + 1} + 1\]\[= -(x^2 + 2x + 1) + 2\]\[= -(x +1)^2 +2\]
Thanks Parth! maybe I should have asked the question differently... assume I don't know the answer but rather I just need to make it contain (x+1)^2 this was actually part of a much larger problem where -x^2-2x+1 is the numerator and (x+1)^2 is in the denominator...it's hard to just know right away which direction to go in...can you offer any tips?
To be honest, it just gets to you. There's no real way to "learn" all of this. But you reach a point where looking at an expression like \(-x^2 - 2x \) triggers you and makes you say, "OH! This sorta looks like \(-x^2 - 2x - 1 = -(x+1)^2\)."
I see what you mean...tell me if this makes sense however...
If I want the top to look like the bottom, I simply write the top portion directly above the bottom... then like you did, with the idea in mind to make it look like the bottom, put parenthesis clearly around (-x^2-2x+1) then -(x^2+2x-1) and then realize that the quantity now looks like the bottom with the exception that the -1 needs to be a +1...so you simply add +2, then rearrange...is that a good strategy that would work everytime you think? :o/
I forgot to mention that before you do any of what I suggested that you foil the bottom first of course
Not sure what you're asking, but yes, that was my thought process.
Okay, then I think I have the technique down then...thanks!:o)
simply a thought he did not add 2 that would have changed the equation
Yeah, um, that's obvious. Adding 2 would be accompanied by subtracting 2.
just wanted her to know you add 1 and add -1
Join our real-time social learning platform and learn together with your friends!