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Imagine rolling two standard six-side dice. What is the P(two even or doubles)
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how many favorable outcomes are possible?
if the two at once is confusing, imagine it as rolling the dice twice
P(even) is, well there are 3 evens out of 6 sides: 1/2 if we roll an even and and even, P(even and even) = 1/2 * 1/2
and since each side has 1/6 of a chance of showing, the probability of rolling the same number twice is: 1/6 * 1/6 but heres a catch, weve already counted some of the doubles: 2,2 4,4 6,6, theres 3 of them
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which is why the formula we have is defied as: P(AorB) = P(A) + P(B) - P(AandB)
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