Question

HELP!!!!! I am so lost and stuck and I don't understand how to solve this problem! I need to solve for X. Help?

Answer 1

how many degrees in a triangle

Answer 2

180

Answer 3

180 - 100

Answer 4

you got this one? :)

Answer 5

yeah

Answer 6

80 - 15 = your answer

Answer 7

so x=65??? really??

Answer 8

yes

Answer 9

hmmm what's "x"

recall your SOH CAH TOA \(\bf {\color{brown}{ sin}}(\theta)=\cfrac{opposite}{hypotenuse}

\\ \quad \\

% cosine
{\color{blue}{ cos}}(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\

% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\)

which one of those, include the

hypotenuse, the angle, and the opposite side?

Answer 10

Um....I really dont know...

Answer 11

lol

Answer 12

its 65

Answer 13

well... look, is there, it'd bite you on the nose

Answer 14

Well they all kind of have the hypotenuse, adjacent, and opposite side!

Answer 15

If I knew what I was doing I wouldn't have come here!

Answer 16

well..... yes and no
thus, recall your SOH CAH TOA

Answer 17

well, that's understandable
that doesn't exempt you from using the trig identities though

Answer 18

if you look in your book, they'd be there as well

Answer 19

Its SOH isnt it? No...CAH. No SOH. Its SOH, right?

Answer 20

WHAT

Answer 21

right... .SOH has the angle, the opposite and the hypotenuse

thus \(\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(15^o)=\cfrac{x}{100}\impliedby \textit{solve for "x"}
\)

Answer 22

I DONT GET IT

Answer 23

hmm? what part?

Answer 24

all

Answer 25

0.258 or rounded up 0.26?

Answer 26

hehe

Answer 27

@Vendela make sure you calculator is in Degree mode
notice that 15 is for 15 degrees

as opposed to Radians mode

Answer 28

Asad786 well, may be you need to revise also your SOH CAH TOA then

Answer 29

0.65?

Answer 30

well... solve for 'x"

Answer 31

x=0.65

Answer 32

hmmm ok so \(\bf a=\cfrac{b}{c}\) solving that for "b", what would that give you?

Answer 33

Whaaaaaaaaaat????

Answer 34

oh wait would it be 65 and not 0.65?

Answer 35

well.. what do you think about \(\bf a=\cfrac{b}{c}\) if you were to solve it for "b" though?

Answer 36

I have no idea what a or b or c is in this equation

Answer 37

just three variables, is all

so... "b" would be.... what do you think? \(\bf a=\cfrac{b}{c}\)

Answer 38

65?

Answer 39

65? hehe.. is only three variables
there are no values... so can't be 65

if you were to solve \(\bf a=\cfrac{b}{c}\) for "b", "b" is?

Answer 40

X?

Answer 41

lemme put it differently
\(\bf 7=\cfrac{b}{3}\) solving that for "b", would be ?

Answer 42

21?

Answer 43

aha! how did you get 21 anyway?

Answer 44

7 times 3

Answer 45

exactly
thus \(\bf a=\cfrac{b}{c}\implies a\cdot c=b\)

and thus

\(\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(15^o)=\cfrac{x}{100}\implies sin(15^o)\cdot 100=x\)

Answer 46

OH MY GOSH YOU ARE BRILLIANT!!!

Answer 47

its still 65

Answer 48

that means you're using radians
meaning your calculator is in Radian mode

in this case is 15 degrees though, not 15 radians
so you need the calculator in Degree mode

Answer 49

25.88

Answer 50

https://www.google.com/search?client=opera&q=sin(15+degrees)*100&sourceid=opera&ie=utf-8&oe=utf-8&channel=suggest&gws_rd=ssl

Answer 51

yeap

Answer 52

YESSS!!! THANK YOU!!!!!

Answer 53

yw

Answer 54

@jdoe0001 can you help me again? I think I did it wrong but I'm not sure

Answer 55

Is this right? Tan(x)= 50/54
50/54= 0.92
Tan(0.92)=

Answer 56

Can anyone help me?

Answer 57

let me check...

Answer 58

It is going to be tan= 54/50 ->> 27/25 so.. angle X= 47.20
@vendela

Answer 59

Ugh I wish I had known that!!! I already turned it in!!! But thank you anyways @fionacndg