Question

Anyone good with matrices? http://gyazo.com/d7cb9abe873683e71611878fa59fbf37

Answer 1

Discrete math?

Answer 2

not sure how to do much with matrices

Answer 3

hmm find \(\large C^{-1}\) is simple, now to decode.. or get that other one... not sure ont that one

Answer 4

im not even sure what they mean when they say decode

Answer 5

\(\textit{inverse of a 2x2 matrix}
\\ \quad \\
A=
\begin{bmatrix}
a&{\color{brown}{ b}}\\c&{\color{brown}{ d}}
\end{bmatrix}\qquad A^{-1}=\cfrac{1}{a\cdot {\color{brown}{ d}}-c\cdot {\color{brown}{ b}}}
\begin{bmatrix}
{\color{brown}{ d}}&-{\color{brown}{ b}}\\-c&a
\end{bmatrix}\)

Answer 6

when they say C^-1 do they want you to find the inverse?

Answer 7

yeap

Answer 8

so the determinant is 13 right

Answer 9

the inverse will also be a 2x2
now

to get a 2x6 "encoded" matrix
from two 2x2 ones.... not sure on that one

I know multiplication of both will only give you the "identity" matrix or \(\begin{bmatrix}
1&0\\0&1
\end{bmatrix}\)

Answer 10

hmmm -3 * -2 = +6

Answer 11

(1*7)-(-3*-2)
7+6=15?

Answer 12

oh i see

Answer 13

so 1/6 [ 7/3 2/1]

Answer 14

im not sure how to make a matrix with the equation thing so thats the best i can do

Answer 15

7+6 = 15? hmmm
what about 7+8?

and -3*-2 = +6
thus

(1*7)-(-3*-2) = 1 - (+6)

Answer 16

1*7 is 7 though

Answer 17

hmm shoot

Answer 18

right typo

7+6 = 15? hmmm
what about 7+8?

and -3*-2 = +6
thus

(1*7)-(-3*-2) = 7 - (+6) => 1

Answer 19

yeah that sounds better

Answer 20

do you have any idea how to decode it

Answer 21

hmmm nope

Answer 22

dang, thanks anyway