The profit of a company is modeled by the equation p(x) = 60x − 2x2 − 2, where p the profit is in thousands of dollars and x is the number of units sold in hundreds. How many units must the company sell to make the maximum profit?
1,000
1,500
2,000
2,500
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OpenStudy (anonymous):
p(x)=60x-2x^2-2
OpenStudy (owlcoffee):
Well, in order to find the maximum profit, we would have to find, the functions maximum value.
And to do that, we have to derivate the function:
\[p(x)=60x-2x^2-2\]
and derivating it:
\[p'(x)=60-4x\]
Then, a maximum is determined when the derivative is zero:
\[60-4x=0\]
\[x=15\]
OpenStudy (anonymous):
so what do I do with the 15?
OpenStudy (owlcoffee):
evaluate it in the original function P(x)
OpenStudy (anonymous):
plug in the 15s for x?
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OpenStudy (owlcoffee):
yes
OpenStudy (anonymous):
60(15)-2(15)^2-2
OpenStudy (anonymous):
I didnt get nowhere near the answers
OpenStudy (owlcoffee):
what did you get?
OpenStudy (anonymous):
448
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OpenStudy (owlcoffee):
yes, it's correct, but I gave you the answer, re-read the question.