Question

can anyone help me in solving these two equations simultaneously ??

Answer 1

you are given 3 equations

Answer 2

and 3 unknowns

Answer 3

yup...i have put the equation 3 in 1 & 2

Answer 4

and you want to determine the steps they got to get an answer?

Answer 5

yes..i m unable to solve it...

Answer 6

after putting the equation 3 in 1 & 2 i have multiplied eq 2 by \[\sqrt{3}\] and then add it to 1...

so i get
\[2F _{CA}\cos \theta + 2\sqrt{3}F _{CA}\sin \theta = 169.91\]

am i right ?? & what should i do after this ???

Answer 7

2F cos(t) -Fcos(30) = 0
2F sin(t) +Fsin(30) -91.1 = 0


2cos(t)-cos(30) = 0
2sin(t)+sin(30) = 91.1/F


cos(t) = cos(30)/2

t = arccos(cos(30)/2) = 64.34

http://www.wolframalpha.com/input/?i=arccos%28cos%2830%29%2F2%29

Answer 8

since we know t, F is easily determined

Answer 9

ok...thank you very much and about 2nd qs ??

Answer 10

id use eq3 to solve for Fbc cost
id use eq4 to solve for Fbc sint

and sub those into eq1 and 2 which turns it into a 2 unknown system of 2 equations

Answer 11

Fba cos(45) -Fcd cos(30) = 0
Fba sin(45) -Fcd sin(30) = 900

Answer 12

90, not 900

Answer 13

and + .... edit

Fba cos(45) -Fcd cos(30) = 0
Fba sin(45) +Fcd sin(30) = 90

can you solve this?

Answer 14

yes....thank you very much....

Answer 15

cos45 = sin 45 sooo subtract one from the other

Fcd cos(30)+Fcd sin(30) = 90

Fcd (cos(30)+sin(30)) = 90

Fcd =90/(cos(30)+sin(30)) = 65.88....

Answer 16

good :)

Answer 17

:-)