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Mathematics 28 Online
OpenStudy (anonymous):

Somebody out there who can help me with functions?

OpenStudy (anonymous):

OpenStudy (owlcoffee):

Now, we have a point. Every point can be viewed as P(x,y) but y is the image of x in the function, so therefore, any point "P" can be viewed as: \[P(x,f(x))\] So given that point, we can conclude that: \[f(-1)=7\] That is using the structure of a point, I just gave you. And, now let's add 3 to it, to make it become: \[f(x+3)=y+3\] and plotting the given point: \[f(-1+3)=7+3\] \[f(2)=10\] And transforming it into a point, a new point we can call "Q": \[Q(2,10)\]

OpenStudy (anonymous):

Actually, i dont think this is correct. Thank you for trying though. :)

OpenStudy (anonymous):

Would you mind if i showed you an example of how its done?

OpenStudy (anonymous):

@Owlcoffee

OpenStudy (owlcoffee):

Sure. I have never done this before haha

OpenStudy (anonymous):

Actually, i think its going to take alot more than an example to explain. :p Here is a link to help you out though: http://www.purplemath.com/modules/fcntrans.htm

OpenStudy (anonymous):

@Owlcoffee

OpenStudy (owlcoffee):

Ah, I see. Well, I learned something new today.

OpenStudy (anonymous):

Yea, I appreciate your effort in trying to help me though! It must have been bothersome to spend that time on one problem only to find that it was wrong. :/

OpenStudy (owlcoffee):

Don't be silly. The best way to learn is to actually make mistakes. I was wrong, but it was worth the new knowledge ;)

OpenStudy (anonymous):

Thats a good way to look at it! :)

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