Question

Graphing parabolas question:

Answer 1

I think you have to put it in standard form idk

Answer 2

awe i wish i knew how to do this to help):

Answer 3

ikr smh lol

Answer 4

No. This is in the perfect form. :P

Answer 5

There's no "k" so is it just 0? Lol

Answer 6

Lol. There is k. Look closely.

Answer 7

Is it (0,0)? Ugh lmao i cant see what u can

Answer 8

Lol. I have an extra air of eyes.

Answer 9

Melissa is that you in the picture?

Answer 10

Yes, it was a bridal shoot! Thats why i look good xD

Answer 11

OK if that's k what is a?! D:

Answer 12

Note down this somewhere. This will help you plot these in the future too.

PS Congratulations on your wedding.

Answer 13

Im not married lol it was just a shoot

Answer 14

Lol. Sorry.
I'll take my congratulations back.

Answer 15

Oh boy, I'm still a little fuzzy on a and k

Answer 16

So basically vertex in your problem is?

Answer 17

(-2,4) ?

Answer 18

Look,
I can write it in two ways,
-1(x-2)^2 + 4
OR
4 - 1(x-2)^2

It's just like writing 2 + 1 OR 1 + 2.

Answer 19

No.
(2, 4)
Because we change the sign of h.

Answer 20

I dont mean to bother, but you literally just added a 1 ? How did you know where to move the numbers

Answer 21

Lol, know what I'm not gonna ask why anymore it all breaks down to because math.

Answer 22

C'mon. This isn't any bother. :P

Remember when your teacher said, "When there's nothing, there's 1".
e.g.
The number 2.
It's is not just 2.
It's 2/1.
Or we can 2*1.

So it multiplying and dividing with 1 at the same time.

Answer 23

When you move the 4, doesn't it have to turn -?

Answer 24

Nope ONLY the term with x.

Basically what we do is:
-1(x-2)^2 + 4.

We take the things in the brackets out. i.e x-2
And set it equal to zero.

x - 2 =0.
And solve it for x like 5th graders do.
x -2 = 0
x = 2.

Answer 25

Hahahahaha, oh okay. So this graph will be turned down?

Answer 26

What's your say? xD

Answer 27

a is negative here.
Means sad face.
Just like "n".

Answer 28

I think it is! Lol yeah so every time math gives me a problem like that I always move the first number and add a 1?

Answer 29

^Lol. I wouldn't say a yes to that. :O

Answer 30

woah wait, you said it can be 4-1(x-2) but a is positive in that example :o

Answer 31

oh boy

Answer 32

How is a positive?
a is the term with parenthesis.
And with parenthesis exists a -1.

Answer 33

but the standard form is y-a(x+h)+k?

Answer 34

oops, y=a(x+h)+k

Answer 35

Yes.
And there's a squared over there.

Answer 36

i hope im not annoying

Answer 37

If you were, I would've left. ^_~

Answer 38

oh yeah there is a squared...but how does it affect a? 4-1 is still 3

Answer 39

Can you add
4 - x?
No.

Why no?
Because 4 - 1x.
Because they both are different terms. 4 is a number and -x is a variable.

Same case here.

Answer 40

4 is a number.
JUST a coefficient.

Whereas -(x-2)^2 is term with x attached to it and squared as well.
So you can't add or subtract 4 with this -1(x-2)^2.

Answer 41

Refer to the attachment.

Answer 42

Oh yes you're right!! @saifoo.khan

Answer 43

Woah how did you do that? @robtobey

Answer 44

I still dont get why it is down turned

Answer 45

i was taught if a<0 it's negative but gee

Answer 46

What I posted was from the Mathematica v9 program.
The In[1] line, requests that the expression 4 - (x - 2)^2 be multiplied out, and then simplified.
The plot was generated in 6.5 milliseconds on a mid 2010 Apple IMac computer.

Answer 47

Why do we just move numbers like nothing, how will you know?

Answer 48

can u help me?