Question

What did I do wrong in this question? I have to find the following integral:

Answer 1

substitute \(u = 3x-2\) and work it step by step

Answer 2

as rational said, let u= 3x-2
then find what dx is
so you get an integral in terms of u
then integrate it with respect to u

Answer 3

u can also expand the integral and then solve

Answer 4

@ozhobbits u got ur mistake?

Answer 5

Can you write it out?

Answer 6

do you the formula of expansion: \[(a+b)^2\]

Answer 7

No.

Answer 8

\[(a+b)^2=a^2+b^2+2ab\]

Answer 9

now expand (3x-2)^2

Answer 10

where
a:3x
b:2

Answer 11

\[here\ the\ formula\ (a-b)^2=a^2-2ab+b^2\ use this formula\]

Answer 12

you are supposed to divide by the differential of the expression inside of the bracket, not multiply