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Chemistry 28 Online
OpenStudy (anonymous):

Can someone explain this question to me? I know how to do the work but I just don't know what it's asking me to do, thanks. When a 14.2g sample of mercury (II) oxide is decomposed into its elements by heating, 13.2g Hg is obtained. What is the percent composition of the compound?

OpenStudy (dtan5457):

Mercury oxide is HgO If you want the percent composition of each element, given that Hg=13.2g just do 13.2/14.2 and 1/14.2 for oxygen

OpenStudy (anonymous):

But I don't know what to do with the given grams and I'm not sure what the question is asking me to find.

OpenStudy (anonymous):

@dtan5457

OpenStudy (dtan5457):

They are asking you for the percent composition per element in the compound in this case it's HG and O

OpenStudy (dtan5457):

For HG it's 13.2/14.2 For O it's 1/14.2 convert to percentages

OpenStudy (anonymous):

I don't get that lol. I mean, I learned that to find percent comp. you do mass of element divided by mass of compound times 100 to find the mass of element. So like, wouldn't I first find the mass of the whole compound?

OpenStudy (dtan5457):

"When a 14.2g sample of mercury (II) oxide "

OpenStudy (anonymous):

I'm sorry I still don't get that part :(

OpenStudy (dtan5457):

That is the mass of the whole compound, 14.2 grams

OpenStudy (anonymous):

Ohhhh ok!

OpenStudy (anonymous):

So to find the mass of Hg aka the percent comp. of Hg, I would do 200.6/14.2 right?

OpenStudy (dtan5457):

it's mass of element/whole compound For HG it's (13.2/14.2)x100

OpenStudy (anonymous):

Wait, but what is 200.6 then? I got that off of the periodic table. But so I'd get the answer by doing 13.2/14.2 times 100 correct?

OpenStudy (anonymous):

So I got 92.96% as the answer. Is that correct?

OpenStudy (dtan5457):

yes

OpenStudy (dtan5457):

and oxygen would just be 100-92.96

OpenStudy (dtan5457):

I don't know where the 200 came from

OpenStudy (anonymous):

Ohhhhhh okay! Omg thank you so much! :) And idk I think I musta did something wrong but still thanks a lot :) I appreciate it.

OpenStudy (dtan5457):

yw

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