Question

Find an equation in standard form for the ellipse with the vertical major axis of length 16, and minor axis of length 4.

x squared divided by 64 plus y squared divided by 4 = 1
x squared divided by 2 plus y squared divided by 8 = 1
x squared divided by 8 plus y squared divided by 2 = 1
x squared divided by 4 plus y squared divided by 64 = 1

Answer 1

@jim_thompson5910

Answer 2

It's an ellipse.

\(\dfrac{x^{2}}{}+\dfrac{y^{2}}{} = 1\)

Vertical Major axis length of 16.

16/2 = 8

So far:

\(\dfrac{x^{2}}{}+\dfrac{y^{2}}{8^{2}} = 1\)

minor axis of length 4.

4/2 = 2

\(\dfrac{x^{2}}{2^{2}}+\dfrac{y^{2}}{8^{2}} = 1\)

Jut one piece at a time. No need to be overwhelmed by the whole thing at once.

Okay, that was your free one. Now, you do one.