a line contains the point (8,-5). if the slope of the line is 5/7, write the equation of the line using point slope form. a. y-5=5/7 (x+8) b. y + 5 = -5/8 (x+7) c. y+8= 5/7( x-5) d. y+5= 5/7(x-8)
@Zale101
Member what we did in the previous post? It is the same thing except that the slope is not 0, it is 5/7. And the point is already give, which is (8,-5) So, this equation is perfect for two methods, the point slope formula or slope intercept form. For point slope formula: \(y-\color{red}{y_1 }=m(x-\color{red}{x_1})\) \(y+5=\frac{5}{7}(x-8)\) For slope intercept form: \(y=mx+b\) Plug everything in x,y=8,-5 m=5/7 and solve for b \(-5=\frac{5}{7}(5)+b\) and then rewrite the equation with m and slope numbers plugged in.
\(-5=\frac{5}{7}(8)+b\) The previous one was an error, sorry for that.
so how do i solve it?? do i multiply??
But everything was correct
oh so its a right?!?!?!
You solve the equation from which one looks easier to you. I find this easier for algebra students, it's pretty straight forward \(y-(-5)=\frac{5}{7}(x-8)\)
so its not a??
It can't be a, it is not the same as this \(y+5=\frac{5}{7}(x-8)\)
And lol, i didnt pay attention to the choices, i would've just choose the first method by using the point slope formula
So which is the right choice?
a?
This choice ? ---> a. y-5=5/7 (x+8)
no it was incorrect. have no idea then
oh ok d then (;
Yes
thx
np, but you already understand how to do these kind of problems now, right?
yes i suppose
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