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Mathematics 22 Online
OpenStudy (anonymous):

How to change simulation pls help

OpenStudy (anonymous):

OpenStudy (anonymous):

#2 and #6

OpenStudy (anonymous):

@micahm

OpenStudy (anonymous):

@nerd_3.14 @pinklion23

OpenStudy (pinklion23):

im hear

OpenStudy (anonymous):

:) can u help??

OpenStudy (pinklion23):

maybe lets see

OpenStudy (anonymous):

ok only #6 for now though

OpenStudy (pinklion23):

um what grade is this

OpenStudy (anonymous):

7th

OpenStudy (anonymous):

@pinklion23

OpenStudy (pinklion23):

im hear okay i should be able to help you

OpenStudy (anonymous):

ok;0

OpenStudy (pinklion23):

omg you gave me a medal how kind i did not give you an answer though

OpenStudy (anonymous):

lol its all right:) haha

OpenStudy (pinklion23):

omg idk im so upset @iGreen might be able to help and @sleepyjess too sooooooo sorry i will keep trying though

OpenStudy (anonymous):

its all right ;)

OpenStudy (pinklion23):

wait how did my computer do that

OpenStudy (anonymous):

wat?

OpenStudy (pinklion23):

my computer just like copied and pasted my earlier post so weird oh well

OpenStudy (anonymous):

haha kk

OpenStudy (sleepyjess):

I can't open the file

OpenStudy (pinklion23):

why not?

OpenStudy (anonymous):

umm wait a sec

OpenStudy (anonymous):

In this experiment, you will be using two coins as a simulation for a real-world compound event. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats. 1. What is the theoretical probability that the family has two dogs or two cats? I say that "heads, heads" is equal to having 2 cats; and "tails, tails" is equal to having 2 dogs. Since I say that, the theoretical probability of having 2 cats is 9/50 and the theoretical probability of having 2 dogs is 11/50. 2. Describe how to use two coins to simulate which two pets the family has. 3. Flip both coins 50 times and record your data in a table like the one below. Result Frequency Heads, Heads  9 Heads, Tails  14 Tails, Heads  16 Tails, Tails  11 Total 50 4. Based on your data, what is the experimental probability that the family has two dogs or two cats? I say that "heads, heads" is equal to having 2 cats; and "tails, tails" is equal to having 2 dogs. Since I say that, the experimental probability will be for 2 cats: 9/50, divide them to get the decimal, you get 0.18. Multiply this by 100 and you get 18%. For 2 dogs: 11/50, divide them to get the decimal and you get 0.22. Multiply it by 100 and you get 22%. So then the experimental probability for the family to have two cats is 18% and for 2 dogs its 22%. 5. If the family has three pets, what is the theoretical probability that they have three dogs or three cats? I say that "heads, heads" is equal to having 3 cats; and "tails, tails" is equal to having 3 dogs. Since I say that, the theoretical probability of having 3 cats is 9/50 and the theoretical probability of having 3 dogs is 11/50. 6. How could you change the simulation to generate data for three pets?

OpenStudy (anonymous):

i need help with #6 first pls

OpenStudy (anonymous):

u there @sleepyjess

OpenStudy (anonymous):

??

OpenStudy (sleepyjess):

What do you think?

OpenStudy (anonymous):

i REALLY have NO IDEA

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

im not sure can u help me sleepyjess pls???

OpenStudy (sleepyjess):

If there are 2 coins for 2 pets, there would be _ coins for 3 pets

OpenStudy (anonymous):

3?

OpenStudy (sleepyjess):

Yep

OpenStudy (anonymous):

:) what else??

OpenStudy (anonymous):

is that IT???!!!?

OpenStudy (sleepyjess):

That's it :)

OpenStudy (anonymous):

wow is it so easy?

OpenStudy (anonymous):

WOW

OpenStudy (anonymous):

can you help me with some more??

OpenStudy (anonymous):

#2

OpenStudy (sleepyjess):

Sometimes we overthink things :)

OpenStudy (anonymous):

and i need someone to check #5 pls

OpenStudy (anonymous):

lol yeah thats true

OpenStudy (sleepyjess):

If heads is cats and tails is dogs, what would you have to do to get a cat and a dog?

OpenStudy (anonymous):

mix it like heads and tails or tails and heads

OpenStudy (sleepyjess):

What would you need to do to the coins to make them show either heads or tails?

OpenStudy (anonymous):

i think....

OpenStudy (anonymous):

hmm

OpenStudy (sleepyjess):

In football to determine which team gets the ball first, what do they do to a coin?

OpenStudy (anonymous):

they flip it?

OpenStudy (sleepyjess):

Yes! So to simulate what pets the family might get, they would need to flip the coins

OpenStudy (anonymous):

ohh........ wow u make it seem SO EASY lol

OpenStudy (anonymous):

is that it to that part?

OpenStudy (anonymous):

and am i right in #5?

OpenStudy (sleepyjess):

I'm pretty sure that is what they want :)

OpenStudy (anonymous):

i dont think so

OpenStudy (anonymous):

oh ok thx

OpenStudy (anonymous):

what about #5?

OpenStudy (anonymous):

If the family has three pets, what is the theoretical probability that they have three dogs or three cats? I say that "heads, heads" is equal to having 3 cats; and "tails, tails" is equal to having 3 dogs. Since I say that, the theoretical probability of having 3 cats is 9/50 and the theoretical probability of having 3 dogs is 11/50.

OpenStudy (sleepyjess):

Well, we know that we need 3 coins for 3 pets, so you would have to get heads heads heads for 3 cats and tails tails tails for 3 dogs

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

yeah but about the probability how do i do that?

OpenStudy (sleepyjess):

the probability thing I'm not really sure on, always have been bad at that, @amistre64 ?

OpenStudy (anonymous):

kk @amistre64

OpenStudy (anonymous):

@Nurali

OpenStudy (anonymous):

ok well ill open a new question @sleepyjess and ill see who comes :) this one is pretty BIG

OpenStudy (sleepyjess):

Okay :)

OpenStudy (amistre64):

this post is rather long and filled with alot of inane chatter, what is the question?

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