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OpenStudy (anonymous):
Critical Points & Inflection Points of
f(x) = e^x-2e^(-x)-3x
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Miracrown (miracrown):
You know what to do here?
OpenStudy (anonymous):
I know that the critical point comes from the 1rst deriv and 2nd deriv gives the inflection point but I'm messing up somewhere :/
Miracrown (miracrown):
You're on the right track! Let's first get the expression for the 1st derivative.
Would you like to work this derivative?
OpenStudy (anonymous):
e^x+2e^(-x)-3
Miracrown (miracrown):
Yep! :)
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Miracrown (miracrown):
To find the critical points (CP), we set this derivative = 0 and solve for x.
Miracrown (miracrown):
\[e ^{x} \space + 2e ^{-x} \space -3 = 0\]
Miracrown (miracrown):
Do you have an idea how to go about solving this equation for x ?
OpenStudy (anonymous):
Good or awful idea to try to ln it?
Miracrown (miracrown):
This won't work unfortunately! :(
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Miracrown (miracrown):
There's actually a "trick" required to solve this equation...
OpenStudy (anonymous):
Okay yeah I'm kind of lost then!
OpenStudy (anonymous):
Obviously can just toss the -3 over
Miracrown (miracrown):
let's first multiply through by e^x
Miracrown (miracrown):
|dw:1427780929395:dw|
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