Critical Points & Inflection Points of f(x) = e^x-2e^(-x)-3x
You know what to do here?
I know that the critical point comes from the 1rst deriv and 2nd deriv gives the inflection point but I'm messing up somewhere :/
You're on the right track! Let's first get the expression for the 1st derivative. Would you like to work this derivative?
e^x+2e^(-x)-3
Yep! :)
To find the critical points (CP), we set this derivative = 0 and solve for x.
\[e ^{x} \space + 2e ^{-x} \space -3 = 0\]
Do you have an idea how to go about solving this equation for x ?
Good or awful idea to try to ln it?
This won't work unfortunately! :(
There's actually a "trick" required to solve this equation...
Okay yeah I'm kind of lost then!
Obviously can just toss the -3 over
let's first multiply through by e^x
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