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Mathematics 16 Online
OpenStudy (anonymous):

Critical Points & Inflection Points of f(x) = e^x-2e^(-x)-3x

Miracrown (miracrown):

You know what to do here?

OpenStudy (anonymous):

I know that the critical point comes from the 1rst deriv and 2nd deriv gives the inflection point but I'm messing up somewhere :/

Miracrown (miracrown):

You're on the right track! Let's first get the expression for the 1st derivative. Would you like to work this derivative?

OpenStudy (anonymous):

e^x+2e^(-x)-3

Miracrown (miracrown):

Yep! :)

Miracrown (miracrown):

To find the critical points (CP), we set this derivative = 0 and solve for x.

Miracrown (miracrown):

\[e ^{x} \space + 2e ^{-x} \space -3 = 0\]

Miracrown (miracrown):

Do you have an idea how to go about solving this equation for x ?

OpenStudy (anonymous):

Good or awful idea to try to ln it?

Miracrown (miracrown):

This won't work unfortunately! :(

Miracrown (miracrown):

There's actually a "trick" required to solve this equation...

OpenStudy (anonymous):

Okay yeah I'm kind of lost then!

OpenStudy (anonymous):

Obviously can just toss the -3 over

Miracrown (miracrown):

let's first multiply through by e^x

Miracrown (miracrown):

|dw:1427780929395:dw|

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