Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (thefurball):

Line integral please help http://prntscr.com/6nkvwg

OpenStudy (jhannybean):

@wio >:)

OpenStudy (anonymous):

try using https://www.wolframalpha.com/

OpenStudy (thefurball):

can you do line integrals there? haven't tried

OpenStudy (thefurball):

I do need to learn this though lol

OpenStudy (anonymous):

furball, do you need help with a parametrization? What is troubling you?

OpenStudy (anonymous):

i dont know it just might help

OpenStudy (thefurball):

I can parameterize them into to different things. I'm just lost from there.

OpenStudy (rational):

|dw:1427782105472:dw|

OpenStudy (anonymous):

To parametrize between two points \(p\) and \(q\), you can use this formula: \[ r(t) =(q-p)t + p,\quad t\in [0,1] \]Because it gives you \(r(0) = p\) and \(r(1) = q\).

OpenStudy (anonymous):

Give me your parametrization then.

OpenStudy (thefurball):

was thinking \[C _{1}: x=4t, y=t\]\[C _{2}: x = t+4, y =1-t\]? That's what I've been doing with line integrals so far

OpenStudy (anonymous):

That will work.

OpenStudy (thefurball):

Ok. What do I plug in for dx and dy?

OpenStudy (anonymous):

Well, for the first one: \[ dx = d(4t) = 4~dt\\ dy = d(t) = dt \]

OpenStudy (anonymous):

For the second one: \[ dx = d(t+4) = dt\\ dy = d(1-t) = -dt \]

OpenStudy (anonymous):

We are using: \[ dx = x'(t)~dt =\frac{dx}{dt}dt \]

OpenStudy (anonymous):

Are you still stuck?

OpenStudy (thefurball):

Got it! Sorry, was working on it lol. Thanks a lot!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!