@iGreen could you see if I got this right?
@phi could you see if I got this right?
@Mertsj Could you see if I got this right?
Got what right?
This problem, here it is. 2. The holding tanks are congruent in size and both are in the shape of a cylinder that has been cut in half vertically. The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 15 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit. We are told to find the volume of two tanks that are congruent and are a cylinder cut in half. So first off, In order to complete this we need the measurements of the tanks in order to plug them into the formula we will use. In the description we are told that tank #1 has a radius of 15 and that tank #2 has a height of 120. Since the tanks are congruent, we can conclude that both tanks have a radius of 15 and a height of 120. So now that we know this, we will use this formula to solve: V = (3.14) (r2)(h). So now that we know what formula to use, lets apply it to this problem. V = (3.14) (r2) (h). V = (3.14) (152) (120). V = (3.14) (225) (120). V = (3.14) (27,000). V = 84,780 This is the volume of both tanks which are congruent, which also means that the volume of tank #1 is 42,390, and the volume of tank #2 is also 42390. So when added together, this of course ends up as 84,780 which is the volume of both tank combined.
*V = (3.14) (15) (120). For the second part in the formula
to the power of two.
Yep, you got it.
Thanks, will have another problem soon, gotta complete it first.
@iGreen Here is my next question. 3. In step 1, you found the volume (in cubic feet) of the main tank. If the maximum density of killer whales per cubic foot is 0.000011142, what is the maximum number of killer whales allowed in the main show tank at any given time? You must explain your answer using words, and you must show all work and calculations to receive credit. For this problem we need find how many killers can fit in the main show tank, so in order to do this we need the volume of the main show tank (359,007) and the maximum density of the killers whales (0.000011142). So in order to see how many killer whales will fit in the tank, we need to multiply the volume of the tank by the density of the killer whales. 359,007 * 0.000011142 = 4.000055994 Now we round our answer to the nearest whole number a get 4. Which means that the maximum number of killer whales that can fit in the main show tank is 4.
One question per post, close this and open a new one.
okay
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