Help, medal + fan! Solve for x please
\[\Large \sqrt{x-2}=\frac{7}{4}-x\]
need help? :)
We got to square both sides first :P
lol why did i even ask that question..... O.o
So @kainui square both sides first, and then set it equal to 0. And you just solve the equation for x.
okay i did the math (which was nothing) and im lost sorry i can't help i tried tho sorry loks like the great smartone is helping you lol
Noob, start off by squaring both sides \[x-2 = (7/4-x)^2\] eliminating the the squarer root, and then afterwards you can expand and move terms all to one side. \[x-2=\frac{ 49 }{ 16 }-\frac{ 7 x}{ 2 }+x^2 \implies x-2-\frac{ 49 }{ 16 }+\frac{ 7x }{ 2 }-x^2=0\] note you can simplify a bit more and then you can factor using the quadratic formula if you wish.
\(\Large \sqrt{x-2}=\frac{7}{4}-x\) \(\Large \left(\sqrt{x-2}\right)^2=\left(\frac{7}{4}-x\right)^2\)
Show me the answer I'm still so stuck...
@Kainui Heard of the CoC though (;
@TheSmartOne no one really follows the CoC anymore....lol
Next step \(\Large x-2=\left(\frac{7}{4}-x\right)^2\)
not saying i don't im just saying i noticed that people doesnt really care about the CoC anymore
I think that the equation has no solutions, since the unique root is x=9/4, which is not acceptable
since the subsequent conditions have to be checked: \[\begin{gathered} 7 - 4x > 0 \hfill \\ x - 2 \geqslant 0 \hfill \\ \end{gathered} \]
Next step :P \(\Large x-2= \frac{49}{16}-\frac{7}{2}x+x^2\)
Right, \[(x-9/4)(x-9/4)\] it has no solutions
Set it equal to 0. And you get the picture.
:O i knew it :( no fair lol (didnt really know) i lost my shot of helping a moderator this sux :(
You lost your chance at proving yourself.
abb0t is the only mod
lol
Notice, we gave steps, so this mod could finish the question but Michele gave the answers and got the gold.
i told you no one cares about the CoC anymore lol
Reported
u reported me? :(
I thought it was a challenge @Astrophysics
isn't it @Kainui
isn't it? @Kainui
Hey, Michele is an amazing helper, she explains everything amazing and leaves the asker with no doubts.
thanks! @TheSmartOne
yeah @Michele_Laino helps people with explations and @Astrophysics don't get mad about the medals that's not what matters the most tho
Haha it was all a giant test, now I have to ban you for answer giving @Michele_Laino ! Nah just kidding, it was a challenge and you were clever enough to figure it out. Fun! =P
She? I thought michele was italian for michael
I was kidding lol.
yes! @alyssa_xo
my autism impairs the ability to read humor
you are great! @Kainui
You are great to Michele :)
thanks! @Astrophysics
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