Assume that I = 4.8A and d = 2.2cm .What is the strength of the magnetic field at the center of the loop in the figure?
i know that the loop is 4pi*10^-7*4.8/2.2 but i think i have to add in the wire. problem is, i don't know the length of the wire. so my munot*i/2r....i don't know how we know what r is for the wire itself. the r for the loop is 1.1, but the wire is straight....no r. i'm lost.
B = mu I / d see here, 2nd item on page: http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/curloo.html
i tried that. 4pi*10^-7*4.8/2.2. i said that above. that answer doesn't work
or rather i did .022
i get 274 10^-6 T
2.74*10^-6 and it's not correct
and neither is 2.74*10^-4
U know d=2.2cm=?m
U know 100cm=1m Right?
U hv to cobvert cgs to mks. Unit
*convert
what is cgs and mks? and yes, i knew to make it .022 meters. i divided it by .022, just typed it in here wrong.
Cgs=cm gm sec
Mks=m kg sec
Right?
B=mew not*i/(2r)
I think u got correct result!!!!
i guess. never heard those units. but either way, i still did 4*10^-7 *4.8/.022 and mastering physics says it's wrong. not sure why.
oh, times pi. forgot to add in pi. it's pretty much bedtime for me so i'm tired.
Mew not=4*pi*10^-7
yeah, i know. just forgot to type it in here. did in my calculator though
Wts the wrong with ur result????!!!!!
no idea. just says inocrrect.
I think u should b correct!!!!!!!
k. i'll email the teacher. time for bed for me. i'm falling asleep.
Ok.. bye
Glad to chat with u
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