Question

Is 2x^2+8x+4!a perfect square.
Yes or no? I think it's no?

Answer 1

Have you tried factoring a constant out first?

Answer 2

Well arent you supposed to try squaring the first and last numbers?

Answer 3

Yes, but if you factor it might be easier: \(\Large 2x^2+8x+4 = 2(x^2+4x+2 )\)

Does the inside look like a perfect square?

Answer 4

Wait no ?
Idk lol im confused

Answer 5

And actually yes, you were right, squaring the last and first terms would help. Do know what number, if square, gives you 2 and 4?

Answer 6

16 squared gives you 4.

Answer 7

And 4 squared givse you two.

Answer 8

The square root of those numbers, yes. Squared tho, only \(\Large \sqrt{2} \) and 2 give you 4 and 2 when squared.

Answer 9

Oh lol sorry i get those two mixed up sometimes XD

Answer 10

So it is a perfect square then?

Answer 11

be right back

Answer 12

ok im back c:

Answer 13

Let's check, a perfect square looks something like \( (a+b)^2 \) or \( (a-b)^2 \)

Since there are no minuses, we'll use the first one and plug in those numbers:
\(\Large [\sqrt{2}x+2 ]^2 \)

And alrightt

Answer 14

So it is then?

Answer 15

If you finish it, you'll get \(\Large 2x^2+4\sqrt{2}x+4 \).. does tha look like the previous problem? :P

Answer 16

No?

Answer 17

lol. Im sorry. Math confuses me XD

Answer 18

@Ness9630

Answer 19

It's not, and sorry, I probably should have done this earlier, but if it was a perfect square, it would only give one root, whereas this one gives us two.

So you're right, no :P

Do you understand what I mean?

Answer 20

Yes i do! Thank you so much c: Your very helpful! Thank you for your time

Answer 21

Alright, and you're welcome \(\LARGE \color{red}{\star^{\color{green}{\star}}} \)