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Chemistry 24 Online
OpenStudy (anonymous):

2. Cooks use baking soda to make cakes light and fluffy. You might have used baking soda yourself. Baking soda is NaHCO3. A 0.1 M solution of baking soda in water has a [H+] of about 4.0 × 10–9. (You may prefer to think of the hydronium ion concentration, [H3O+], as 4.0 × 10–9.) Write the formula for the calculation of pH, and then show each step as you calculate the pH of a 0.1 M solution of baking soda.

OpenStudy (aaronq):

Since you already have the hydronium ion concentration, use the formula for pH: \(\sf \Large pH=-log[H_3O^+]\)

OpenStudy (anonymous):

I got that part down...i am just not sure i'm plugging in mu numbers right... ph= -log [4.0 x10^-9]???

OpenStudy (aaronq):

yeah, that's right

OpenStudy (anonymous):

I guess this is where I get stuck in my math

OpenStudy (aaronq):

all you gotta do is plug it into the calculator, there isn't an analytical way to solve logarithms

OpenStudy (anonymous):

then i must be plugging it in wrong with the 10^-9

OpenStudy (aaronq):

yeah, i think so try putting the negative exponent in brackets, like 10^(-9)

OpenStudy (aaronq):

and also put the whole number in brackets -log(number)

OpenStudy (anonymous):

guess it dont work on a regular calculator

OpenStudy (aaronq):

use this http://web2.0calc.com/

OpenStudy (anonymous):

ph=8.4?

OpenStudy (anonymous):

-8.4

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