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Find the area of the region bounded by the curves y = x^–1/2, y = x^–2, y = 1, and y = 3.
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@phi
did you solve the previous problem?
yes I did, sorry I was away and came back to it.
I believe the answer is integral (1,3) x^-1/2 - x^-2
Which would give me 2sqrt3 - 8/3
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Is that correct?
Here is a plot
So does that mean it is actually integral (3,1) or was I right?
you have to think more clearly do you get the idea of "thin rectangles" ? you have two choices: |dw:1427925902521:dw|
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