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A period of a simple pendulum is 2.4s. The length of the pendulum is doubled. What is the period T of the longer pendulum
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\[T = 2\pi \sqrt{\frac{L}{g}}\] nuff said?
For first case T1=2*pi*root(L1/g) 2.4=2*pi*root(L/g).............(1)
For second case T2=2*pi*root(L2/g) T2=2*pi*root(2L/g)..........(2)
Now u hv to divide eqution 2 by equation 1
U will get T2/2.4=root(2) T2=?
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