Ask your own question, for FREE!
Chemistry 15 Online
OpenStudy (bloomlocke367):

Can anyone help me with half-life?

OpenStudy (bloomlocke367):

@phi An element has a half-life of 30 years. If 1.0mg of this element decays over a period of 90 years, how many mg would remain?

OpenStudy (phi):

the equation is \[ A= A_0\left(\frac{1}{2}\right)^\frac{t}{30} \] that says if t is 30 you would get \[ A= A_0\left(\frac{1}{2}\right)^\frac{30}{30} \\A= A_0\left(\frac{1}{2}\right) \] i.e. you would have 1/2 left, just as you are supposed to.

OpenStudy (phi):

replace t with 90 and replace A0 with 1 mg

OpenStudy (phi):

can you do that?

OpenStudy (bloomlocke367):

0.125 mg?

OpenStudy (phi):

you should get (1/2) ^ (90/30) 90/30 is 3 so (1/2)^3 which means 1/2 *1/2 *1/2 = 1/8

OpenStudy (phi):

and yes 1/8 * 1 mg = 0.125 mg

OpenStudy (bloomlocke367):

so that's it?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!